Integrand size = 13, antiderivative size = 19 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {\left (a+b x^3\right )^6}{18 a x^{18}} \]
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Time = 0.00 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {270} \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {\left (a+b x^3\right )^6}{18 a x^{18}} \]
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Rule 270
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a+b x^3\right )^6}{18 a x^{18}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(69\) vs. \(2(19)=38\).
Time = 0.00 (sec) , antiderivative size = 69, normalized size of antiderivative = 3.63 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {a^5}{18 x^{18}}-\frac {a^4 b}{3 x^{15}}-\frac {5 a^3 b^2}{6 x^{12}}-\frac {10 a^2 b^3}{9 x^9}-\frac {5 a b^4}{6 x^6}-\frac {b^5}{3 x^3} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(57\) vs. \(2(17)=34\).
Time = 3.66 (sec) , antiderivative size = 58, normalized size of antiderivative = 3.05
method | result | size |
gosper | \(-\frac {6 b^{5} x^{15}+15 a \,b^{4} x^{12}+20 a^{2} b^{3} x^{9}+15 a^{3} b^{2} x^{6}+6 a^{4} b \,x^{3}+a^{5}}{18 x^{18}}\) | \(58\) |
default | \(-\frac {5 a \,b^{4}}{6 x^{6}}-\frac {5 a^{3} b^{2}}{6 x^{12}}-\frac {a^{4} b}{3 x^{15}}-\frac {a^{5}}{18 x^{18}}-\frac {b^{5}}{3 x^{3}}-\frac {10 a^{2} b^{3}}{9 x^{9}}\) | \(58\) |
norman | \(\frac {-\frac {1}{18} a^{5}-\frac {1}{3} a^{4} b \,x^{3}-\frac {5}{6} a^{3} b^{2} x^{6}-\frac {10}{9} a^{2} b^{3} x^{9}-\frac {5}{6} a \,b^{4} x^{12}-\frac {1}{3} b^{5} x^{15}}{x^{18}}\) | \(59\) |
risch | \(\frac {-\frac {1}{18} a^{5}-\frac {1}{3} a^{4} b \,x^{3}-\frac {5}{6} a^{3} b^{2} x^{6}-\frac {10}{9} a^{2} b^{3} x^{9}-\frac {5}{6} a \,b^{4} x^{12}-\frac {1}{3} b^{5} x^{15}}{x^{18}}\) | \(59\) |
parallelrisch | \(\frac {-6 b^{5} x^{15}-15 a \,b^{4} x^{12}-20 a^{2} b^{3} x^{9}-15 a^{3} b^{2} x^{6}-6 a^{4} b \,x^{3}-a^{5}}{18 x^{18}}\) | \(60\) |
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (17) = 34\).
Time = 0.24 (sec) , antiderivative size = 57, normalized size of antiderivative = 3.00 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {6 \, b^{5} x^{15} + 15 \, a b^{4} x^{12} + 20 \, a^{2} b^{3} x^{9} + 15 \, a^{3} b^{2} x^{6} + 6 \, a^{4} b x^{3} + a^{5}}{18 \, x^{18}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (15) = 30\).
Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 3.21 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=\frac {- a^{5} - 6 a^{4} b x^{3} - 15 a^{3} b^{2} x^{6} - 20 a^{2} b^{3} x^{9} - 15 a b^{4} x^{12} - 6 b^{5} x^{15}}{18 x^{18}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (17) = 34\).
Time = 0.20 (sec) , antiderivative size = 57, normalized size of antiderivative = 3.00 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {6 \, b^{5} x^{15} + 15 \, a b^{4} x^{12} + 20 \, a^{2} b^{3} x^{9} + 15 \, a^{3} b^{2} x^{6} + 6 \, a^{4} b x^{3} + a^{5}}{18 \, x^{18}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 57 vs. \(2 (17) = 34\).
Time = 0.26 (sec) , antiderivative size = 57, normalized size of antiderivative = 3.00 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {6 \, b^{5} x^{15} + 15 \, a b^{4} x^{12} + 20 \, a^{2} b^{3} x^{9} + 15 \, a^{3} b^{2} x^{6} + 6 \, a^{4} b x^{3} + a^{5}}{18 \, x^{18}} \]
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Time = 0.04 (sec) , antiderivative size = 59, normalized size of antiderivative = 3.11 \[ \int \frac {\left (a+b x^3\right )^5}{x^{19}} \, dx=-\frac {\frac {a^5}{18}+\frac {a^4\,b\,x^3}{3}+\frac {5\,a^3\,b^2\,x^6}{6}+\frac {10\,a^2\,b^3\,x^9}{9}+\frac {5\,a\,b^4\,x^{12}}{6}+\frac {b^5\,x^{15}}{3}}{x^{18}} \]
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